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An AI tutor for NEET

Stuck? Your tutor asks the one question that gets you unstuck, then guides you to the answer. That's Socratic learning.

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An example session. The question is from JEE Main 2026.

JEE Main 2026 · Physics

Kinematics

A gas balloon is going up with a constant velocity of 10 m/s. When this balloon reached a height of 75 m, a stone is dropped from it and balloon keeps moving up with the same velocity. The height of the balloon when the stone hits the ground is _______ m. (Take g = 10 m/s²)

  • A85
  • B150
  • C129
  • D125

Rough work

  1. Crossed out: 75 = 5t², so t = 3.9 s
  2. Crossed out: 75 + 10 × 3.9 = 114
  3. y = 75 + 10t − 5t²
  4. 5t² − 10t − 75 = 0, t = 5
  5. Balloon: 75 + 10 × 5 = 125

Solved

Polaris, your AI tutor

Polaris, your AI tutor: I'm right here. Tell me what you've tried, or where it stopped making sense.

You: I got 114, but that's not one of the options.

Polaris, your AI tutor: Talk me through your first line, 75 = 5t². Why did you use that?

You: It falls 75 m from rest, so I used s = ½gt².

Polaris, your AI tutor: That's the trap in this question. Read the first sentence again. Seen from the ground, was the stone at rest just before it was dropped?

You: No, it was moving with the balloon. But how do I write its height now?

Polaris, your AI tutor: This is about initial velocity. Anything let go from a moving object starts with that object's velocity.

You: So it starts at 10 m/s, going up.

Questions about NEET

Which exams is it for?

JEE and NEET. Physics, chemistry and maths for JEE Main. Physics, chemistry and biology for NEET. How the tutor works for JEE Main

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Yes. Coaching covers the lecture. FlowPrep covers the hours after it, with lessons to read, problems to work, revision, and a tutor beside you when you get stuck.

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